Abby Yount gets Girl Scouting top honor

Published 9:46 am Thursday, October 4, 2018

Abby Yount of Mocksville earned the Girl Scout Gold Award, the highest award in Girl Scouting.

Yount, daughter of David and Janell Yount and a member of Girl Scout Troop 41166, worked in partnership with the Davie County Senior Center to host a workshop to teach people how to use their phones and the apps.

“Earning the Girl Scout Gold Award designation is truly a remarkable achievement, and this young woman exemplifies leadership in all its forms,” said Lane Cook, chief executive officer of Girl Scouts Carolinas Peaks to Piedmont. “She saw a need in her community and took action. Her extraordinary dedication, perseverance and leadership, is making the world a better place.”

The Gold Award represents the highest achievement in Girl Scouting; it recognizes girls in grades 9-12 who demonstrate extraordinary leadership through sustainable and measurable “Take Action” projects. After the minimum requirements are completed, the Gold Award project is the culmination of a girl’s demonstration of self-discipline, leadership ability, time management, creativity, initiative and a significant mastery of skills.

Each girl must dedicate a minimum of 80 hours to planning and implementing her project, which must benefit the community and have long lasting impact.

Some universities and colleges offer scholarships to Gold Award recipients, and girls who enlist in the U.S. Armed Forces may receive advanced rank for their achievements.